Dear JC

`x^2 - by^2 = 1`

and `x^2 - by^2 = - 1`

, but I am interested in the more general`x^2 - by^2 = c`

Now I know if we have one solution `(p,q)`

then we can find infinitely many solutions with `(p - q\sqrt {b})(r - s\sqrt {b})^n`

where `(r,s)`

is the first solution to `x^2 - by^2 = 1`

My question is, how do we know when we have all the "primitive" solutions

`(p,q)`

that will generate all the solutions? (Also, is it possible that there would be infinite primitive solutions?) Sincerely,

Badly Learning Odd Wacked Math Equations

Dear Badly,

NERD!!!!

Dear Badly,

NERD!!!!

Ever Patient and Kind,

Jesus H. Christ

Jesus H. Christ

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